APTITUDE solved problems on Time and Distance, RS Agarwal Book Type
These formulas and problems are really helpful to crack various competitive exams in INDIA, just solve the following problems.
Formulas to remember for Time and Distance problems
1. Keep in mind only s=vt (distance= velocity X time ) derive other from this only.
2. Always give attention to units. remember only 1km/hr = 5/18 m/s [ to convert Km/hr to m/s (smaller unit) you have to multiply with small fraction i.e. 5/18 ]
3. Relative velocity – imagine the problem and add or substrata the velocities according to problem (if moving toward each other then add the velocities, If moving in same direction substrata the velocities)
4. Suppose a man covers a distance at velocity x m/s and an returns the same path at at y m/s, then the average speed during the whole journey is (2xy/x+y)m/s
5. Always solve problem by assuming variable like x and solve to find its value.
Now solve the following problem. It will be 100 time better if you keep pen and paper now. Even if you think you can solve the problem, you should try to get the answer by your own attempt now. You will be master in time and distance problems for all the exam like cat, mat, managements, Bank PO, railways etc exam after solving following problems.
Questions-
1. Superheroes Liza and Tamar leave the same camp and run in opposite directions. Liza runs 1 mile per second (mps) and Tamar runs 2 mps. How far apart are they in miles after 1 hour?
Ans- opposite direction velocity, so add velocities=> v(r)= 1+2= 3 mps, from s= vt, s= 3*3600=10800 mile(remember to convert hr in second)
2. Two trains, 200 and 160 meters long take 1 minute to cross each other while traveling in the same direction and take only 10 seconds when they cross in opposite directions. What are the speeds at which the trains are traveling?
Ans- S= 200+160= 360. from x=vt, 360= (x+y)*10, 360= (x-y)60, => x= 21, y= 15
3. A ship went on a voyage after 180 miles a plane started with 10 times speed that of the ship. Find the distance when they meet from starting point.
Ans- 180 + (d/10) = d d = 20 ans is 180+20= 200 miles.
4. A person covered some distance in 12 hours. He covered half the distance by rail @ 75 km per hour and the rest by car @ 45 km/hr. The total distance covered by him was
ans- 676 km.
5. A train crosses a pole in 15 seconds, while it crosses 100 meter long platform in 25 seconds. The length of the train is -
ans- 60
6. Sanjay wants to reach the Railway station at 10.00 am. The station is 10 km away from his house. If Satish walks at the speed of 4 km/hour at what time shall he start from his home?
7. A man covers a distance on bike .If He had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower he would have taken 40min more.the distance is.
s/(v+3)= (s/v)-(2/3),
s/(v-2)= (s/v)+(2/3),
add both equestion, solving gives v= 12, from 1st equestion, s=40 8.
8. A person starts from hill top A, goes downhill, then along a plain and finally climbs to hill top B. He takes a total of 4 hours for the jouney travelling downhill @72kmph, on plains @63kmph and uphill @56kmph. However while returning back, from B to A, he takes 4 hours 40 mins with speeds being same. Find distance AB [CAT Examination question]
Ans- 273 km
9.Rita covers a certain distance by a car traveling at a speed of 70 km/h and returns at the starting point riding on a scooter at the speed of 55 km/h. Find her average speed for the whole journey.
ans- 61.6
10.- A man and a woman 81 miles apart from each other, start traveling towards each other at the same time. If the man covers 5 miles per hour to the women’s 4 miles per hour, how far will the woman have traveled when they meet?
Ans-
Time taken to meet = Distance between them / Relative speed
= 81/(4 + 5) = 9 hours
Therefore, woman travells = 9 x 4 = 36 miles.
11..A boat goes 50 Km upstream in 10 hours and a distance of 40 Km. Down stream is 9 hours. The speed of the boat in standing water is
After solving above problem you can easily crack the Time and Distance problems asked at TCS, infosys, wipro etc. You can find similar questions at RS Agarwal Book.
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42 Responses to “APTITUDE solved problems on Time and Distance, RS Agarwal Book Type”
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thank you for the model test papers.
it will prove a great help to me
i am not understanding how questions 4,5 & 6 are solved?Plz send me reply.Plz how they are solved?what’s the technique?
Can i please know the solution for Question 8.
what r the chapters i should do from r.s aggarwal for tcs & cts.
which book i have to refer for infosys?
plzzz sen me model question papers for CEt..
can u pls send me some queries nd its solution,2 prepare 4 tcs
can please some question for TCS for their market research profile aptitude
please explain me about 5,6,7,8,9,10,11 in details.thankyou
IN A 100 M RACE A CAN BEAT B B 5 M AND B CAN BEAT C BY 10 M . BY HOW MUCH DISTANCE CAN A BEAT C IN THE RACE
Can i please know the solution for Question 9
hi, how question number 3,4,5 are solved please send the rply.whats the formula used for that type of problems.plz send rply
hi, how question number 3,4,5 are solved please send the rply.whats the formula used for that type of problems
Can i please know the solution for Question 8.
can u plz send me explanation for 1,2,3,4,5
I am not understanding question 4 .Plz send my reply how to solve this problem with explanation.
hi shikha
the answer for question 4 is 675..use t=d/s instead of d=t/s…
how to get placed in mnc’s? what are the techniques to be followed?
maja aa gaya ustaad
aanand laa diye
can you send me some more information on this topic?
Can u plz send me some Accenture’s aptitude questions for Human Resource ??????
this is very helpful to me. so i want ur updated aptitude question on my mail .
Thanks u for the model papers. this is verygood
hi friends these questions are very useful to all the students,so keep updated with rs agarwal
pls can tell me the solution for question 7,9
can i know the explnation of all the question
plz any body send me appitute (with solving answers)of ebook download site. i have zero knowledge of appitute plzzzzz help guys
hi sir,
i m looking for tricks to solve all the aptitude questions which comes in exams..
can u help me by providing the tricks for everything.
i m looking for a job in software field so.
plz help me
thanks and regards
Vivek Kumar
hi sir,
i m looking for tricks to solve all the aptitude questions which comes in exams..
can u help me by providing the tricks for everything.
thanks and regards
by divagaran
hi sir,
i m looking forward to questions which r useful for banking exams… pls get me tat with solutions…
hi sir,
i m looking for tricks to solve all the aptitude questions which comes in exams..
can u help me by providing the tricks for everything.
plz send some intial basic apptitude questions
related to placement for engg.
can u plz send me questions related to aptitude test held before the interviews.
Hi Sir
PLZ send some tricks to be followed while performing aptitude tests..Plz help me..
hai the following is 4th question answer
4th ans:- ((d/2)/75) + ((d/2)/45) = 12
then d=676
5th question ans : L/15 = (L+100)/25 ==> L=150
8th ans : (d1/72)+(d2/63)+(d3/56)=4
(d1/56)+(d2/63)+(d3/72)= 4 2/3
ans is d1+d2+d3 = 271 (total distance)
8th ans : (x/(x/70)) + (x/(x/55)) ==> 125
avg = 125/2 = 62.5
pls send de explanation for de following:
3. A ship went on a voyage after 180 miles a plane started with 10 times speed that of the ship. Find the distance when they meet from starting point.
4. A person covered some distance in 12 hours. He covered half the distance by rail @ 75 km per hour and the rest by car @ 45 km/hr. The total distance covered by him was
5. A train crosses a pole in 15 seconds, while it crosses 100 meter long platform in 25 seconds. The length of the train is -
which book i will prepare for infosys aptitude test please suggest me sir
I want the full explanation of this formula of this particular problem.How the formula is derived???
A’s Speed : B’s Speed = ((b)^1/2 : (a)^1/2)
1.Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:???
And what shall be the correct answer???
QUESTION NO 3
Let’s say the ship is travelling – v miles/hr
and plane took ‘t’ hours to meet the ship
Than, vt is the distance ship travelled after plane started
(10v)t = 10vt is the distance plane travelled.
So we have, vt + 180 = 10vt
or 9vt = 180
or vt = 20
Hence distance ==> 180 + 20 = 200 miles